Tuesday, July 18, 2017

Lint 201.Segment Tree Build

The structure of Segment Tree is a binary tree which each node has two attributes start and end denote an segment / interval.
start and end are both integers, they should be assigned in following rules:
  • The root's start and end is given by build method.
  • The left child of node A has start=A.left, end=(A.left + A.right) / 2.
  • The right child of node A has start=(A.left + A.right) / 2 + 1, end=A.right.
  • if start equals to end, there will be no children for this node.
Implement a build method with two parameters start and end, so that we can create a corresponding segment tree with every node has the correct start and end value, return the root of this segment tree.

/**
 * Definition of SegmentTreeNode:
 * public class SegmentTreeNode {
 *     public int start, end;
 *     public SegmentTreeNode left, right;
 *     public SegmentTreeNode(int start, int end) {
 *         this.start = start, this.end = end;
 *         this.left = this.right = null;
 *     }
 * }
 */
public class Solution {
    /**
     *@param start, end: Denote an segment / interval
     *@return: The root of Segment Tree
     */
    public SegmentTreeNode build(int start, int end) {
        // write your code here
        if (start > end) return null;
        SegmentTreeNode result = new SegmentTreeNode(start, end);
        if (start == end) return result;
        int mid = (start + end) / 2;
        SegmentTreeNode left = build(start, mid);
        SegmentTreeNode right = build(mid + 1, end);
        result.left = left;
        result.right = right;
        return result;
    }
}

No comments:

Post a Comment